The vector equation of the plane passing through the line r - a - b and parallel to the line r - c - d is A- - r - c b d -0B- -r-a- c-d-0C- -r-a- b-d-0D- -r-c- a-d-0

The correct option is C [(r a)bd]=0 nbsp;Plane contain the line r=a+ λb nbsp;and parallel to the line r=c+μd ∴ nbsp;It is passing through a and parallel ...

The vector eq...

Question

The vector equation of the plane passing through the line $\to r = \to a + λ \to b$ and parallel to the line $\to r = \to c + μ \to d$ is

[(\to r - \to a) \to b \to d] = 0

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[(\to r - \to a) \to c \to d] = 0

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[(\to r - \to c) \to b \to d] = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[(\to r - \to c) \to a \to d] = 0

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Solution

The correct option is C $[(\to r - \to a) \to b \to d] = 0$
Plane contain the line $\to r = \to a + λ \to b$ and parallel to the line
$\to r = \to c + μ \to d$
$∴$ It is passing through $\to a$ and parallel to $\to b \times \to d$
So the equation will be $[(\to r - \to a) \to b \to d] = 0$

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The vector equation of the plane passing through the line →r=→a+λ→b and parallel to the line →r=→c+μ→dis

The correct option is C [(→r−→a)→b→d]=0 Plane contain the line →r=→a+λ→b and parallel to the line →r=→c+μ→d ∴ It is passing through →a and parallel to →b×→d So the equation will be [(→r−→a)→b→d]=0

The vector equation of the plane passing through the line $\to r = \to a + λ \to b$ and parallel to the line $\to r = \to c + μ \to d$ is

The correct option is C $[(\to r - \to a) \to b \to d] = 0$
Plane contain the line $\to r = \to a + λ \to b$ and parallel to the line
$\to r = \to c + μ \to d$
$∴$ It is passing through $\to a$ and parallel to $\to b \times \to d$
So the equation will be $[(\to r - \to a) \to b \to d] = 0$