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Question


The vector having magnitude of 12 units in the direction of the A=3^i+2^j6^k
is

A
36^i+24^j72^k
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B
(36^i+24^j72^k)7
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C
12^i+12^j12^k
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D
(3^i+2^j6^k)7
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Solution

The correct option is B (36^i+24^j72^k)7
We need vector in the direction of 3^i+2^j6^k, so first we will calculate the unit vector in the direction of the given vector
^A=A|A|=3^i+2^j6^k32+22+(6)2=3^i+2^j6^k7

Now on multiplying the unit vector with the magnitude, we will get the required vector.
12×3^i+2^j6^k7=36^i+24^j72^k7
so, option B is the correct answer.

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