The correct option is C 4^i+6^j
The given vector is 2^i+3^j
Let it be →a
If →a and →b are linearly dependent, then
x→a+y→b=0 where x and y are not simultaneously zero.
Now, among the given vectors, let's consider 4^i+6^j
If it is linearly dependent with 2^i+3^j, then
x(2^i+3^j)+y(4^i+6^j)=0 When x and y are not simultaneously 0
When x = 2 and y = -1, x(2^i+3^j)+y(4^i+6^j)=0
Thus, 4^i+6^j is linearly dependent with 2^i+3^j