The vector →a which is collinear with the vector →b=^i−3^j+^k and satisfies the condition →a⋅→b=22 is
A
2^i+8^j−2^k
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B
2^i−6^j+2^k
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C
2^i−8^j−2^k
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D
2^i−6^j−2^k
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Solution
The correct option is B2^i−6^j+2^k If →a is collinear with →b, then→a=x→b
here, x is some scalar ⇒→a⋅→b=x→b⋅→b=22 ⇒x(^i−3^j+^k)⋅(^i−3^j+^k)=22 ⇒x(1+9+1)=22 ⇒11x=22 ⇒x=2 →a=x→b=2(^i−3^j+^k) ∴→a=2^i−6^j+2^k