The vector projection of a vector 3^i+4^k on y-axis is
Step 1: Given that:
A vector, let →A = 3^i+4^j
Step 2: Formula and concept used:
The component of →A along →B = Acosθ
Thus,
The projection of →A along →B = Acosθ.^B
But, we know that;
→A.→B=ABcosθ
⇒Acosθ=→A.→BB
Thus,
The projection of →A along →B
=(→A.→B)B.→BB
⇒(→A.→B).→BB2
The vector along Y- the axis, let →B = ^j
Step 3: Calculation of projection of the given vector on Y-axis:
= (3^i+4^k).^j1.^^j
= 0
(As, ^i.^j=^k.^j=0 )
Thus,
The projection of the given vector on Y-axis will be zero.