The correct option is C ^j−^k
Let →r be coplanar with given two vectors
∴ →r=x(^i+^j+2^k)+y(^i+2^j+^k) ...(i)
Also, →r is perpendicular to vector (^i+^j+^k)
∴ →r.(^i+^j+^k)=0
⇒ (x+y),+(x+2y)+(2x+y)=0
⇒ 4(x+y)=0
⇒y=−x
∴ From (i), →r=x(^i+^j+2^k−^i+2^j−^k)
=x(−^j+^k)
Taking x=±1,
→r=−^j+^k or →r=^j−^k