The vector a-b- bisects the angles between the vectors a- and b- if

The correct option is C |a⃗|=|b⃗| From the above figure cos θ | a⃗+b⃗ | | a⃗ |= (a⃗+b⃗)· #160;a⃗ #160; #160; #160; #160; #160; #16 ...

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Section Formula

The vector ...

Question

The vector $\to a + \to b$ bisects the angles between the vectors $\to a$ and $\to b$ if

| \to a | = 1

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| \to b | = 1

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| \to a | = | \to b |

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\to a . \to b = 0

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Solution

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\to a

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\to a . \to b = \to a . \to c, \to a \times \to b = \to a \times \to c, \to a \neq 0

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\to a \cdot \to b < 0

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μ = \to a . \to b + \to b . \to c + \to c . \to a

| \to a | = 1; ∣ ∣ \to b ∣ ∣ = 4; | \to c | = 2

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