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Question

The vectors 2i^+3j^-4k^ and ai^+bj^+ck^ are perpendicular if
(a) a = 2, b = 3, c = −4
(b) a = 4, b = 4, c = 5
(c) a = 4, b = 4, c = −5
(d) a = −4, b = 4, c = −5

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Solution

(b) a = 4, b = 4, c = 5

It is given that vectors 2i^+3j^-4k^ and ai^+bj^+ck^ are perpendicular. So, their dot product is zero.2a+3b-4c=0b a=4; b=4; c=524+34-45=08+12-20=00=0, which is true.


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