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Question

The vectors a=xi−2j+5k and b=i+yj−zk are collinear if

A
x=1,y=2,z=5
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B
x=1/2,y=4,z=10
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C
x=1/2,y=4,z=10
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D
x=1,y=2,z=5.
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Solution

The correct options are
A x=1,y=2,z=5
B x=1/2,y=4,z=10
C x=1/2,y=4,z=10
D x=1,y=2,z=5.
The given vectors are collinear if a=kb for some k
i.e xi2j+5k=ki+kyjzkk
(xk)i+(2ky)j+(5+zk)k=0
Hence x=k,y=2/k and
z=5/k. Taking k=1,1/2,1/2 and 1 we get the values given by (a),(b),(c) and (d), respectively

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