The vectors AB-3i-5j-4k and AC-5i-5j-2k are side of a - ABC- The length of the median through A is-

The correct option is C 5 unitsPosition vector of AD =(3+5)i+(5 5)j+(4+2)k/2 AD=8i+6k/2=4i+3k ∴ Length of median =|AD|=√(16+9)=5 uni ...

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Medians of a Triangle and the Drawing Method

The vectors ...

Question

The vectors $A B = 3 i + 5 j + 4 k$ and $A C = 5 i - 5 j + 2 k$ are side of a $Δ A B C$ . The length of the median through $A$ is:

\sqrt{13}

units

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2 \sqrt{5}

units

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5

units

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10

units

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Solution

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Similar questions

- - \to A B = 3 ˆ i + 5 ˆ j + 4 ˆ k

- - \to A C = 5 ˆ i - 5 ˆ j + 2 ˆ k

¯ ¯¯¯¯¯¯ ¯ A B = - 3 ¯ i + 4 ¯ ¯ ¯ k

¯ ¯¯¯¯¯¯ ¯ A C = 5 ¯ i - 2 ¯ j + 4 ¯ ¯ ¯ k

A B C

A

C

A = 3 ˆ i - 5 ˆ j + ˆ k

B = 2 ˆ i + 3 ˆ j - 4 ˆ k

C

\to A B = - 3 ˆ i + 4 ˆ k

\to A C = 5 ˆ i - 2 ˆ j + 4 ˆ k

Δ

A

¯ ¯ ¯ a = 3 ¯ i - 4 ¯ j + 2 ¯ ¯ ¯ k, ¯ ¯ b = 2 ¯ i - ¯ j - 6 ¯ ¯ ¯ k

¯ ¯ c = 5 ¯ i - 5 ¯ j - 4 ¯ ¯ ¯ k

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