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Byju's Answer
Standard XII
Mathematics
Shortest Distance between Two Skew Lines
The vectors ...
Question
The vectors
¯
a
=
x
^
i
−
2
^
j
+
5
^
k
and
¯
b
=
^
i
+
y
^
j
−
z
^
k
are collinear if
A
x
=
1
,
y
=
−
2
,
z
=
−
5
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B
x
=
1
/
2
,
y
=
−
4
,
z
=
−
10
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C
x
=
−
1
/
2
,
y
=
4
,
z
=
−
10
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D
x
=
−
1
,
y
=
2
,
z
=
5
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Solution
The correct option is
A
x
=
1
,
y
=
−
2
,
z
=
−
5
we have,
→
a
=
x
^
i
−
x
^
j
+
5
^
k
and
→
b
=
^
i
+
y
^
j
−
z
^
k
Now, to have collinearity,
both vectors will be identical.
∴
x
=
1
,
y
=
−
2
,
and
z
=
−
5
Ans
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0
Similar questions
Q.
If the vectors
x
^
i
+
^
j
+
^
k
,
^
i
+
y
^
j
+
^
k
and
^
i
+
^
j
+
z
^
k
are co-planar where
x
≠
1
,
y
≠
1
,
z
≠
1
, then prove that
1
1
−
x
+
1
1
−
y
+
1
1
−
z
=
1
.
Q.
Solve the following system of equations by matrix method:
(i)
x
+
y
−
z
= 3
2
x
+ 3
y
+
z
= 10
3
x
−
y
− 7
z
= 1
(ii)
x
+
y
+
z
= 3
2
x
−
y
+
z
= − 1
2
x
+
y
− 3
z
= − 9
(iii) 6
x
− 12
y
+ 25
z
= 4
4
x
+ 15
y
− 20
z
= 3
2
x
+ 18
y
+ 15
z
= 10
(iv) 3
x
+ 4
y
+ 7
z
= 14
2
x
−
y
+ 3
z
= 4
x
+ 2
y
− 3
z
= 0
(v)
2
x
-
3
y
+
3
z
=
10
1
x
+
1
y
+
1
z
=
10
3
x
-
1
y
+
2
z
=
13
(vi) 5
x
+ 3
y
+
z
= 16
2
x
+
y
+ 3
z
= 19
x
+ 2
y
+ 4
z
= 25
(vii) 3
x
+ 4
y
+ 2
z
= 8
2
y
− 3
z
= 3
x
− 2
y
+ 6
z
= −2
(viii) 2
x
+
y
+
z
= 2
x
+ 3
y
−
z
= 5
3
x
+
y
− 2
z
= 6
(ix) 2
x
+ 6
y
= 2
3
x
−
z
= −8
2
x
−
y
+
z
= −3
(x)
x
−
y
+
z
= 2
2
x
−
y
= 0
2
y
−
z
= 1
(xi) 8
x
+ 4
y
+ 3
z
= 18
2
x
+
y
+
z
= 5
x
+ 2
y
+
z
= 5
(xii)
x
+
y
+
z
= 6
x
+ 2
z
= 7
3
x
+
y
+
z
= 12
(xiii)
2
x
+
3
y
+
10
z
=
4
,
4
x
-
6
y
+
5
z
=
1
,
6
x
+
9
y
-
20
z
=
2
;
x
,
y
,
z
≠
0
(xiv)
x
−
y
+ 2
z
= 7
3
x
+ 4
y
− 5
z
= −5
2
x
−
y
+ 3
z
= 12
Q.
Show that each one of the following systems of linear equation is inconsistent:
(i) 2x + 5y = 7
6x + 15y = 13
(ii) 2x + 3y = 5
6x + 9y = 10
(iii) 4x − 2y = 3
6x − 3y = 5
(iv) 4x − 5y − 2z = 2
5x − 4y + 2z = −2
2x + 2y + 8z = −1
(v) 3x − y − 2z = 2
2y − z = −1
3x − 5y = 3
(vi) x + y − 2z = 5
x − 2y + z = −2
−2x + y + z = 4
Q.
Find the angle between the following pair of lines:
(i)
x
−
2
2
=
y
−
1
5
=
z
+
3
−
3
and
x
+
2
−
1
=
y
−
4
8
=
z
−
5
4
(ii)
x
2
=
y
2
=
z
1
and
x
−
5
4
=
y
−
2
1
=
z
−
3
8
Q.
If
→
a
=
x
^
i
+
2
^
j
−
z
^
k
and
→
b
=
3
^
i
−
y
^
j
+
^
k
are two equal vectors, then write the value of
x
+
y
+
z
.
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