1
Question
The vectors →a=^i+2^j+3^k;¯b=2^i−^j+^k & →c=3^i+^j+4^k are so placed that the end point of one vector is the starting point of the next vector.Then the vectors are
The vectors →a=^i+2^j+3^k;¯b=2^i−^j+^k & →c=3^i+^j+4^k are so placed that the end point of one vector is the starting point of the next vector.Then the vectors are
Open in App
Solution
The correct option is C coplanar but can form a triangle
→b−→a=^i−3^j−2^k
→c−→b=^i+2^j+3^k
→a−→c=−2^i+^j−^k
Their modulii are such that the sum of two sides is greater than the third side.
Thus, they can form a triangle.
→b−→a=^i−3^j−2^k
→c−→b=^i+2^j+3^k
→a−→c=−2^i+^j−^k
Their modulii are such that the sum of two sides is greater than the third side.
Thus, they can form a triangle.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
