CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The vectors b and c are non-colinear, if a×(b×c)+(ab)b=(42xsiny)b+(x21)c and (cc)a=c then

A
x=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y=(4n+1)π2, nI
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
y=(2n+1)π2, nI
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A x=1
C y=(4n+1)π2, nI
a×(b×b)+(ab)b =(42xsiny)b+(x21)c(ac)b(ab)c+(ab)b =(42xsiny)b+(x21)c(i)

We know that,
(cc)a=c(cc)ac=ccac=1

1+ab=42xsiny and x21=(ab)

1+1x2=42xsinysiny=x22x+2siny=(x1)2+1

We know that,
1siny1 and
(x1)2+11
So the solution will be,
siny=1y=(4n+1)π2, nI
and x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dot Product
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon