The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. the root mean square velocity of molecules will be ____ (in m/s)

8.41

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70.8

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Zero

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6.8

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Solution

The correct option is B 8.41
$v_{r m s}^{2} = \frac{v_{1}^{2} + v_{2}^{2} + v_{3}^{2} + v_{4}^{2} + v_{5}^{2}}{5} = \frac{(- 10)^{2} + 15^{2} + 2^{2} + (- 3)^{2} + (- 4)^{2}}{5} = 70.8 m^{2} / s^{2}$
$\Rightarrow v_{r m s} = \sqrt{70.8} = 8.41 m / s$

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The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. the root mean square velocity of molecules will be ____ (in m/s)

The correct option is B 8.41v2rms=v21+v22+v23+v24+v255=(−10)2+152+22+(−3)2+(−4)25=70.8m2/s2⇒vrms=√70.8=8.41m/s

The correct option is B 8.41
$v_{r m s}^{2} = \frac{v_{1}^{2} + v_{2}^{2} + v_{3}^{2} + v_{4}^{2} + v_{5}^{2}}{5} = \frac{(- 10)^{2} + 15^{2} + 2^{2} + (- 3)^{2} + (- 4)^{2}}{5} = 70.8 m^{2} / s^{2}$
$\Rightarrow v_{r m s} = \sqrt{70.8} = 8.41 m / s$