You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Root Mean Square Speed

The velocitie...

Question

The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. the mean velocity of the molecules will be ______ (in m/s)

8.14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Zero
$v_{a v g} = \frac{v_{1} + v_{2} + v_{3} + v_{4} + v_{5}}{5} = \frac{- 10 + 15 + 2 - 3 - 4}{5} = \frac{0}{5} = 0$

Suggest Corrections

Similar questions

The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. The mean speed of the molecules will be

The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. the root mean square velocity of molecules will be ____ (in m/s)

Q. A gas consists of

5

molecules with a velocity of

5 {m s}^{- 1}

10

molecules with a velocity of

3 {m s}^{- 1}

and

6

molecules with a velocity of

6 {m s}^{- 1}

. The ratio of average velocity and rms velocity of the molecules is

9.5 \times 10^{- x}

. Value of

x

is:

Q. If a gas contains 5 molecules with a velocity of 2 m/s, 10 molecules with a velocity of 3 m/s and 5 molecules with a velocity of 6 m/s.

(a) Calculate rms velocity (m/sec).
(b What average speeds (m/sec)?

Q. A gas consists of

5

molecules with a velocity of

5 {m s}^{- 1}

10

molecules with a velocity of

3 {m s}^{- 1}

and

6

molecules with a velocity of

6 {m s}^{- 1}

. The ratio of average velocity and rms velocity of the molecules is

9.5 \times 10^{- x}

. Value of

x

is:

Join BYJU'S Learning Program

The velocities of five molecules of a gas are -10 m/s, 15 m/s, 2m/s, -3 m/s and -4 m/s respectively. the mean velocity of the molecules will be ______ (in m/s)

The correct option is C Zerovavg=v1+v2+v3+v4+v55=−10+15+2−3−45=05=0

The correct option is C Zero
$v_{a v g} = \frac{v_{1} + v_{2} + v_{3} + v_{4} + v_{5}}{5} = \frac{- 10 + 15 + 2 - 3 - 4}{5} = \frac{0}{5} = 0$