The velocities of sound at the same temperature in two monoatomic gases of densities p1 and p2 are v1 and v2 respectively. If p1/p2=4, then the value of v1/v2 is
A
14
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B
2
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C
12
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D
4
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Solution
The correct options are A14 C12 For velocity of sound in gas v=√pγp [P is pressure and p is density of gas, γ is Cp/Cv] Here, v1=√γPp1 and v2=√γPp2 v1v2=√p2p1=√14=12