Question

The velocities of the ends '$A$' and '$B$" of the rod, namely $V_A$ and $V_B$, respectively.

• A. $v_A=\frac{5}{32}{v}_0;v_B=\frac{1}{32}{v}_0$
• B. $v_A=\frac{7}{32}{v}_0;v_B=\frac{3}{32}{v}_0$
• C. $v_A=\frac{7}{32}{v}_0;v_B=\frac{1}{32}{v}_0$
• D. $v_A=\frac{5}{32}{v}_0;v_B=\frac{3}{32}{v}_0$

Answer 1

The correct option is C $v_A=\frac{7}{32}{v}_0;v_B=\frac{1}{32}{v}_0$

$V_A=\frac{v_o}{8}+w\left(OA\right)$

$V_A=\frac{v_o}{8}+\frac{3v_o}{128l}\times 4l$

$V_A=\frac{7}{32}{v}_o$

$V_B=\frac{v_o}{8}-w\left(OB\right)$

$V_B=\frac{v_o}{8}-\frac{3v_o}{128l}\times 4l$

$V_B=\frac{1}{32}{v}_o$