The velocities of three molecules A- B and C of a gas are 1- -3 and -5 ms-1- The value of their rms velocity will be

The correct option is A 1.73 ms^ 1 V_rms = √(1^2 + (√(3))^2 +( √(5))^2/3) = √(3)m/s (we have used the standard result of root mean square velocity) ...

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Standard XII

Physics

Relative Velocity in 2D

The velocitie...

Question

The velocities of three molecules A, B and C of a gas are 1, $\sqrt{3}$ and $\sqrt{5} m s^{- 1}$ . The value of their rms velocity will be

1.73 m s^{- 1}

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2 m s^{- 1}

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4 m s^{- 1}

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9 m s^{- 1}

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Solution

The correct option is A $1.73 m s^{- 1}$
$V_{r m s} = \sqrt{\frac{1^{2} + (\sqrt{3})^{2} + (\sqrt{5})^{2}}{3}} = \sqrt{3} m / s$ (we have used the standard result of root mean square velocity)

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The velocities of three molecules A, B and C of a gas are 1, √3 and √5ms−1. The value of their rms velocity will be

The correct option is A 1.73ms−1Vrms=√12+(√3)2+(√5)23=√3m/s (we have used the standard result of root mean square velocity)

The velocities of three molecules A, B and C of a gas are 1, $\sqrt{3}$ and $\sqrt{5} m s^{- 1}$ . The value of their rms velocity will be

The correct option is A $1.73 m s^{- 1}$
$V_{r m s} = \sqrt{\frac{1^{2} + (\sqrt{3})^{2} + (\sqrt{5})^{2}}{3}} = \sqrt{3} m / s$ (we have used the standard result of root mean square velocity)