The velocity and acceleration vectors of a particle undergoing circular motion are →v=2^im/s and →a=2^i+4^jm/s2 respectively at an instant of time. The radius of the circle is
A
1m
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B
2m
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C
3m
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D
4m
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Solution
The correct option is A1m
Given,
→v=2^ims−1vx=2,vy=0
→a=(2^i+4^j)ms−2ax=2,ay=4
Tangential velocity in circular motion give, centripetal acceleration toward center
Centripetal acceleration is normal to the tangential velocity