Question

The velocity constant of a reaction at $290K$ was found to be $3.2\times {10}^{-3}{s}^{-1}$. When the temperature is raised to $310K$, it will be about:

• A. $6.4\times {10}^{-3}$
• B. $3.2\times {10}^{-4}$
• C. $9.6\times {10}^{-3}$
• D. $1.28\times {10}^{-2}$

Answer 1

The correct option is D $1.28\times {10}^{-2}$

For every 10 degree rise in the temperature, the rate of the reaction doubles.
When temperature is increased from 290 K to 300 K, the rate of the reaction doubles from $3.2\times {10}^{-3}s$ to $6.4\times {10}^{-3}s$.
When temperature is increased from 300 K to 310 K, the rate of the reaction doubles from $6.4\times {10}^{-3}s$ to $1.28\times {10}^{-2}s$.