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Question

The velocity-displacement graph for a car on a straight road is shown in figure


Determine the acceleration of the car at s=150 m.

A
62.5 m/s2
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B
114 m/s2
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C
15.625 m/s2
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D
10.75 m/s2
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Solution

The correct option is C 15.625 m/s2
Referring to the vs graph,
Slope of graph for 100 m<s<200 m
Slope=dvds=7550200100=25100=14
Equation of the above part of graph is
(v50)=14(s100)

Let v1 be velocity when s=150 m
Then, v150=14[150100]
v1=50/4+50=62.5 m/s
So, acceleration when s=150 m will be
a=dvdt=vdvds=62.5×14
a=15.625 m/s2

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