The correct option is C 15.625 m/s2
Referring to the v−s graph,
Slope of graph for 100 m<s<200 m
Slope=dvds=75−50200−100=25100=14
Equation of the above part of graph is
(v−50)=14(s−100)
Let v1 be velocity when s=150 m
Then, v1−50=14[150−100]
v1=50/4+50=62.5 m/s
So, acceleration when s=150 m will be
a=dvdt=vdvds=62.5×14
a=15.625 m/s2