wiz-icon
MyQuestionIcon
MyQuestionIcon
2088
You visited us 2088 times! Enjoying our articles? Unlock Full Access!
Question

The velocity-displacement graph for a car on a straight road is shown in figure


Determine the acceleration of the car at s=150 m.

A
62.5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
114 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15.625 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10.75 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 15.625 m/s2
Referring to the vs graph,
Slope of graph for 100 m<s<200 m
Slope=dvds=7550200100=25100=14
Equation of the above part of graph is
(v50)=14(s100)

Let v1 be velocity when s=150 m
Then, v150=14[150100]
v1=50/4+50=62.5 m/s
So, acceleration when s=150 m will be
a=dvdt=vdvds=62.5×14
a=15.625 m/s2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon