The velocity of a body as a function of time is $V = t^{3} - 6 t^{2} + 10 t + 4$ . The correct increasing order of accelerations of a body at the given following time instant will be :
a) $t = 0 s e c$
b) $t = 1 s e c$
c) $t = 5 s e c$

b, a, c

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a, b, c

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c, b, a

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c, a, b

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Solution

The correct option is A b, a, c
$a = \frac{d V}{d t} = \frac{d}{d t} (t^{3} - 6 t^{2} + 10 t + 4) = 3 t^{2} - 12 t + 10$
a) $a_{(a t t = 0)} = 3 (0)^{2} - 12 (0) + 10 = 10 m / s^{2}$
b) $a_{(a t t = 1)} = 3 (1)^{2} - 12 (1) + 10 = 1 m / s^{2}$
c) $a_{(a t t = 5)} = 3 (5)^{2} - 12 (5) + 10 = 25 m / s^{2}$
Therefore, the correct sequence is b < a < c.

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The velocity of a body as a function of time is V=t3−6t2+10t+4. The correct increasing order of accelerations of a body at the given following time instant will be :a) t=0 sec b) t=1 sec c) t=5 sec

The correct option is A b, a, ca=dVdt=ddt(t3−6t2+10t+4)=3t2−12t+10a) a(att=0)=3(0)2−12(0)+10=10m/s2b) a(att=1)=3(1)2−12(1)+10=1m/s2c) a(att=5)=3(5)2−12(5)+10=25m/s2Therefore, the correct sequence is b < a < c.

The velocity of a body as a function of time is $V = t^{3} - 6 t^{2} + 10 t + 4$ . The correct increasing order of accelerations of a body at the given following time instant will be :
a) $t = 0 s e c$
b) $t = 1 s e c$
c) $t = 5 s e c$