The velocity of a body of mass 2 kg changes from v 1-2 i -3 j - k - m - s to v 2-3 i -2 j -3 k - m - s in 3 sec under the influence of a external force- Findthe magnitude of the force applied - A- 5-1 NB- 4-8 NC- 4-3 ND- 4 N

The correct option is C 4.3 N Change in momentum, ∆P=mv2 mv1 nbsp;∆P=m[( 3i^ nbsp;+2j^ nbsp;+3k^) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Question

The velocity of a body of mass $2 k g$ changes from $v_{1} = 2 ˆ i + 3 ˆ j - ˆ k m / s$ to $v_{2} = - 3 ˆ i + 2 ˆ j + 3 ˆ k m / s$ in $3 s e c$ under the influence of a external force. Find the magnitude of the force applied ?

5.1 N

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4.8 N

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4.3 N

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4 N

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Solution

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2 k g

v_{1} = 2 ˆ i + 3 ˆ j - ˆ k m / s

v_{2} = - 3 ˆ i + 2 ˆ j + 3 ˆ k m / s

3 s e c

s^{- 1}

s^{- 1}

_{1} = 4^i m/s

_{2} = 3^j m/s

Δ t = 2 s

m = 10 kg

2 k g

F = (2 ˆ i - 3 ˆ j + 4 k)

r = (3 ˆ i + 2 ˆ j + 3 ˆ k)

τ = r \times F

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