The velocity of a body of rest mass mo is -32 c where c is the velocity of light in vacuum- The mass of this body is -

The correct option is C 2m_o By special theory of relativity m' = γ m= m_0√(1 v^2c^2) m' = #160;m_0√(1 34) =m_0(1/2)= 2m_0 ...

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Mass Energy Equivalence

The velocity ...

Question

The velocity of a body of rest mass $m_{o}$ is $\frac{\sqrt{3}}{2} c$ (where c is the velocity of light in vacuum). The mass of this body is :

(\frac{\sqrt{3}}{2}) m_{o}

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(\frac{1}{2}) m_{o}

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3 m_{o}

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2 m_{o}

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Solution

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m_{0}

M S + 2 O_{2} \to M S O_{4};

2 M S + 3 O_{2} \to 2 M O + 2 S O_{2}

M S + 2 M O \to 3 M + S O_{2};

M S + M S O_{4} \to 2 M + 2 S O_{2}

M

M S + 2 O_{2} ⟶ M {S O}_{4}

2 M S + 3 O_{2} ⟶ 2 M O + 2 S O_{2}

M S + 2 M O ⟶ 3 M + S O_{2}

M S + M {S O}_{4} ⟶ 2 M + 2 S O_{2}

M S + 2 O_{2} \to M S O_{4};

2 M S + 3 O_{2} \to 2 M O + 2 S O_{2}

M S + 2 M O \to 3 M + S O_{2};

M S + M S O_{4} \to 2 M + 2 S O_{2}

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