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Question

The velocity of a car travelling on a straight road is 3.5kmh−1 at an instant of time. Now travelling with uniform acceleration for 10s the velocity becomes exactly double. If the wheel radius of the car is 25cm, then which of the following is the closest to the number of revolutions that the wheel makes during this 10s?

A
84
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B
95
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C
126
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D
135
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Solution

The correct option is B 95
Initial velocity is 3.5 kmh
Time taken =10 s, Final velocity =7kmh
Radius of the wheel (r) =25 cm
Using, v=u+at
7=3.5+a×103600
a=3.5×360km/h

Angular acceleration =ar
Angular Velocity =ur
From: θ=ω×t+12×α×t2
Net rotation of the wheel will be calculated and θ2π will give total no. of revolutions 95.

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