The velocity of a freely falling body one second after being dropped is
9.8 m/s
Any body in free fall is under acceleration due to gravity,g and thus accelerates at 9.8 ms−2.
Using equation of motion:
v=u+at, where u=0, a=9.8 ms−2 and t=1 s, we get
v=9.8×1=9.8ms−1
Thus, it will have a velocity of 9.8 ms−1 in the downward direction.