Question

The velocity of a moving particle along the x-axis is given as $v=x^2-5x+4\left(in\text{m/s}\right),$ where x denotes the $x-coordinate$ of the particle in meters. Find the magnitude of the acceleration of the particle when the velocity of the particle is zero?

• A. $0m/s^2$
• B. $2m/s^2$
• C. $3m/s^2$
• D. None of these

Answer 1

The correct option is A $0m/s^2$

Given,

Velocity $v=x^2-5x+4$

now, the acceleration

$a=\frac{dv}{dt}$

$a=2x\frac{dx}{dt}-5x\frac{dx}{dt}$

given that, $v=\frac{dx}{dt}=0$

so, $a=2x\times 0-5\times 0$

$a=0m/se{c}^2$

so, the acceleration is zero,when the velocity is zero.