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Byju's Answer
Standard IX
Physics
Velocity
the velocity ...
Question
the velocity of a moving particle is given by v=\sqrt{4x} if at t=0 particle is at x=0, then velocity and acceleration at t=2
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Similar questions
Q.
Velocity in
m
/
s
of a particle moving along
x
−
axis varies with time as
v
=
(
10
+
5
t
−
t
2
)
. At time
t
=
0
,
x
=
0.
Acceleration of particle at
t
=
2
s
is
x
m
/
s
2
, then value of
x
is
Q.
A particle is moving along x-axis has acceleration
f
at time
t
, given by
f
=
f
0
(
1
−
t
T
)
, where
f
0
and
T
are constants. The particle at
t
=
0
has zero velocity. In the time interval between
t
=
0
and the instant when
f
=
0
, the velocity(
v
a
) of the particle is then
Q.
The position of a particle moving in the xy-plane at any time is given by
x
=
(
3
t
2
−
6
t
)
metres,
y
=
(
t
2
−
2
t
)
metres. Select the correct statement about the moving particle from the following
Q.
A particle moving along
x
−
axis has acceleration
f
, at time
t
, given by
f
=
f
0
(
1
−
t
T
)
,
where
f
0
and T are constants. The particle at
t
=
0
has zero velocity. In the time interval between
t
=
0
and the instant when
f
=
0
, the particle's velocity
v
x
is:
Q.
A particle travels so that its acceleration is given by
→
a
=
5
c
o
s
t
^
i
−
3
s
i
n
t
^
j
. If the particle is located at
(
−
3
,
2
)
at time
t
=
0
and is moving with a velocity given by
(
−
3
^
i
+
2
^
j
)
. Find
(i) the velocity
[
→
v
=
∫
→
a
.
d
t
]
t
i
m
e
t
(ii) the position vector
[
→
r
=
∫
→
v
.
d
t
]
of the particle at time
(
t
>
0
)
.
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