The velocity of a particle depends upon as v = a + bt + $c t^{2}$ ; if the velocity is in m/sec, the unit of a will be

m / s e c

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m / s e c^{2}

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m^{2} / s e c

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m / s e c^{3}

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Solution

The correct option is A $m / s e c$
Quantities of similar dimensions can be added or subtracted so unit of a will be same as that of velocity.

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c t^{2}

c t^{2}

The velocity of a particle $v = a + b t + c t^{2}$ . If the velocity is in $\frac{m}{s}$ , the unit of a will be:

v = a + b t + c t^{2}

t

a

b

v = a + b t + c t^{2}

{m s}^{- 1}

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