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Question

The velocity of a particle is given by $$v = 12 + 3(t + 7t^{2})$$. What is the acceleration of the particle?


A
3+21t
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B
3+42t
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C
42t
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D
4t
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Solution

The correct option is B $$3+42t$$

Given: $$v=12+3(t+7t^2)$$

$$\Rightarrow v=12+3t+21t^2$$

Now, we know that

$$a=\dfrac{dv}{dt}$$

So,
$$a=\dfrac{d(12+3t+21t^2)}{dt}=3+42t$$.

Mathematics

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