Question

# The velocity of a particle is given by $$v = 12 + 3(t + 7t^{2})$$. What is the acceleration of the particle?

A
3+21t
B
3+42t
C
42t
D
4t

Solution

## The correct option is B $$3+42t$$Given: $$v=12+3(t+7t^2)$$$$\Rightarrow v=12+3t+21t^2$$Now, we know that$$a=\dfrac{dv}{dt}$$So,$$a=\dfrac{d(12+3t+21t^2)}{dt}=3+42t$$.Mathematics

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