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Byju's Answer

Standard XII

Physics

Relating Circular Motion to SHM

The velocity ...

Question

The velocity of a particle is V=V0+gt+ft if its position is X=0 at t=0 then it's displacement after unit time t=1 is

A) V0 +(g/2) +(f/3)

B) V0 +g +f

C) V0 + (g/2) + f

D) V0 + 2g + 3f

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Solution

According to the question after integrating we will get X=Vot+g/2×t^2+f/2×t^2

If t=1,
X=Vo+g/2+f/2

But this answer is not in the question.

I think the question is mistaken and the real question is V=Vo+gt+ft^2
.

Then the answer will be option A)

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The velocity of a particle is V=V0+gt+ft if its position is X=0 at t=0 then it's displacement after unit time t=1 is A) V0 +(g/2) +(f/3) B) V0 +g +f C) V0 + (g/2) + f D) V0 + 2g + 3f

According to the question after integrating we will get X=Vot+g/2×t^2+f/2×t^2 If t=1, X=Vo+g/2+f/2 But this answer is not in the question. I think the question is mistaken and the real question is V=Vo+gt+ft^2 ​​​​​. Then the answer will be option A)

The velocity of a particle is V=V0+gt+ft if its position is X=0 at t=0 then it's displacement after unit time t=1 is

A) V0 +(g/2) +(f/3)

B) V0 +g +f

C) V0 + (g/2) + f

D) V0 + 2g + 3f

According to the question after integrating we will get X=Vot+g/2×t^2+f/2×t^2

If t=1,
X=Vo+g/2+f/2

But this answer is not in the question.

I think the question is mistaken and the real question is V=Vo+gt+ft^2
.

Then the answer will be option A)