The velocity of a particle moving along a line is v=t2−5t+6, from t=4 to t=8. What is the relation between distance (S) and displacement (ΔX)
Velocity-time equation of a particle moving in a straight line is v = 2t - 4 for t ≤ 2 s and v = 4-2t for t> 2 s. The distance travelled by the particle in the time interval from t = 0 to t = 4 s is (Here, t is in second and v in m/s)
Figure shows the velocity-time graph of a particle moving in a straight line.
(i) State the nature of motion of particle.
(ii) Find the displacement of particle at t=6 s.
(iii) Does the particle change its direction of motion?
(iv) Compare the distance travelled by the particle from 0 to 4 s and from 4 s to 6 s.
(v) Find the acceleration from 0 to 4 s and retardation from 4 s to 6 s.