The velocity of a particle moving in a straight line is decreasing at the rate of 3 m/s per metre of displacement at an instant when the velocity is 10 m/s. Determine the acceleration of the particle at this instant.

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Solution

$a = v \frac{d v}{d s} \Rightarrow a = 10 \times 3 = 30 m / s^{2}$

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The velocity of a particle moving in a straight line is decreasing at the rate of 3 m/s per metre of displacement at an instant when the velocity is 10 m/s. Determine the acceleration of the particle at this instant.

a=vdvds⇒a=10×3=30m/s2

$a = v \frac{d v}{d s} \Rightarrow a = 10 \times 3 = 30 m / s^{2}$