the velocity of a particle varies with position x as v = beta x^{-2n} where n and beta are cons†an ts. the acceleration of particle is

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Q. A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to

v (x) = β x^{- 2 n}

.Where,

β

and

n

are constants and

x

is the position of the particle. Find The acceleration of the particle as a function of

x

, if

n = 2

Q. A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to

v (x) = β x^{- 2 n}

, where

β

and

n

are constants and

x

is the position of the particle. The acceleration of the particle as a function of

x

, is given by

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $v (x) = β x^{- 2 n}$ ,where $β$ and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :