The velocity of a projectile at the initial point A is (2^i+3^j)m/s. Its velocity (in m/s) at point B is
A
−2^i−3^j
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B
−2^i+3^j
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C
2^i−3^j
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D
2^i+3^j
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Solution
The correct option is C2^i−3^j
When the projectile hits back the ground again,
the X-component of its initial projected velocity remains unchanged and the Y-component reverses because of same horizontal level (magnitude same while direction becomes opposite).