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Question

The velocity of an electron in a certain Bohr's orbit of H-atom bears the ratio 1:550 to the velocity of light. The quantum number n of the orbit is:

A
n = 2
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B
n = 5
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C
n = 3
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D
n = 4
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Solution

The correct option is D n = 4
Given that:
Velocity of electron=1550×velocity of light
But we know velocity of electron in Bohr orbit is:
Vn=2.19×108×Zncm/sec2.19×108×1n=1550×3×1010n=2.19×108×5503×1010=4
Hence answer is 4.

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