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Deducing Mathematically

The velocity ...

Question

The velocity of end A of rigid rod placed between two smooth surfaces is $\sqrt{6}$ m/s along horizontal direction. Velocity of end B of that rod is (rod always remains in contact with the given surfaces):

A

2 \sqrt{3} m / s

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B

\sqrt{3} m / s

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C

2 m/s

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D

3 m/s

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Solution

The correct option is C 3 m/s
Velocity component along the rod shall be same at both the points A and B.
Therefore,
$V_{A} C o s 30^{0} = V_{B} C o s 45^{0}$
$V_{B} = \sqrt{\frac{3 X 6}{2}}$
$V_{B} = 3 m / s$

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