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Question

The velocity of light in two different media are 2×108 ms1 and 2.5×108 ms1 respectively. The critical angle for these media is

A
sin1(14)
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B
sin1(12)
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C
sin1(45)
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D
sin1(15)
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Solution

The correct option is C sin1(45)
crspeed of light in rarer medium

cdspeed of light in denser medium.

As we know, the critical angle is,

sin C=1μ=1(crcd)

sin C=cdcr=2×1082.5×108=2025

sin C=45

C=sin1(45)

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

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