Question

The velocity of projection of a projectile is given by : $\overrightarrow{u}=5\hat{i}+10\hat{j}$. Find maximum height.

• A. $8m$
• B. $3m$
• C. $10m$
• D. $5m$

Answer 1

The correct option is D $5m$

As we know that, $H_{max}$=$\frac{U^2}{2g}$
and in projectile motion the vertical component will show the height, so here $\hat{j}$ will be vertical component and horizontal component $\hat{i}$ will be zero.

Therefore,
$H_{max}$=$\frac{{10}^2}{20}=\frac{100}{20}=5m/sec$