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Standard XII

Physics

Acceleration

The velocity ...

Question

The velocity of the particle at any time t is given by $v = 2 t (3 - t) m s^{- 1}$ . At what time is its velocity maximum?

2 s

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3 s

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\frac{2}{3}

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\frac{3}{2}

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Solution

The correct option is D $\frac{3}{2}$ s
$v = 2 t (3 - t) = - 2 t^{2} + 6 t$

$\frac{d v}{d t} = - 4 t + 6$

For V maximum or minimum

$\frac{d v}{d t} = 0, t = \frac{3}{2} s e c$

Option :D

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The velocity of the particle at any time t is given by v=2t(3−t)m s−1. At what time is its velocity maximum?

The correct option is D 32 sv=2t(3−t)=−2t2+6t dvdt=−4t+6For V maximum or minimum dvdt=0,t=32secOption :D

The velocity of the particle at any time t is given by $v = 2 t (3 - t) m s^{- 1}$ . At what time is its velocity maximum?

The correct option is D $\frac{3}{2}$ s
$v = 2 t (3 - t) = - 2 t^{2} + 6 t$

$\frac{d v}{d t} = - 4 t + 6$

For V maximum or minimum

$\frac{d v}{d t} = 0, t = \frac{3}{2} s e c$

Option :D