Question

The velocity of the particle at any time t is given by $v=2t(3-t)$m $s^{-1}$. At what time is its velocity maximum?

• A. 2s
• B. 6s
• C. 1.5s
• D. 1s

Answer 1

The correct option is C 1.5s

Given, velocity $v=2t(3-t)$

$\frac{ds}{dt}=2t(3-t)$

The condition for maxima or minima is $\frac{ds}{dt}=0;2t(3-t)=0$

$2t=0;3-t=0t=3$

At 3s, the velocity will be maximum.