Question

The velocity of waves in a string fixed at both ends is 2 m/s. The string forms standing waves with nodes 5.0 cm apart. The frequency of vibration of the string in Hz is

[SCRA 1998]

• A. 40
• B. 30
• C. 20
• D. 10

Answer 1

The correct option is C

20

Here $\frac{\lambda }{2}=5.0cm\Rightarrow \lambda =10cm$

Hence n = $\frac{v}{\lambda }=\frac{200}{10}=20Hz.$