Question

The velocity- time graph of a body is given in figure. The maximum acceleration in ${\text{ms}}^{-2}$ is

• A. $1$
• B. $4$
• C. $3$
• D. $2$

Answer 1

The correct option is C $3$

Given $v-t$ curve as

Acceleration from $0$ to $20\text{s}$ will be $a=\frac{v_2-v_1}{t_2-t_1}=\frac{20-0}{20-0}=1$
Acceleration from $20$ to $30\text{s}$ will be $a=\frac{v_2-v_1}{t_2-t_1}=\frac{20-20}{30-20}=0$
Acceleration from $30$ to $50\text{s}$ will be $a=\frac{v_2-v_1}{t_2-t_1}=\frac{60-20}{50-30}=2$
Acceleration from $50$ to $70\text{s}$ will be
$a=\frac{v_2-v_1}{t_2-t_1}$
$=\frac{0-60}{70-50}=-3{\text{m/s}}^2$
So, comparing the magnitude in each interval we can say that the maximum acceleration is $3{\text{m/s}}^2$