Question

The velocity-time graph of a body is shown below The displacement covered by body is $5s$ is $v\left(m/s\right)$

• A. $2m$
• B. $4m$
• C. $3m$
• D. $1m$

Answer 1

The correct option is A $2m$

Let $0s$ to $1s$ the area is $A_1$, $1s$ to $2s$ the area is $A_2$, $2s$ to $3s$ the area is $A_3$, $3s$ to $4s$ the area is $A_4$, $4s$ to $5s$ the area is $A_5$.

Since, the displacement is equal to the area enclosed in velocity time graph where area below time axis is negative.

The displacement is given as,

$d=A_1+A_2+A_3+A_4-A_5$

$d=\left(1\times 1\right)+\left(\frac{1}{2}\times 1\times 1\right)+\left(\frac{1}{2}\times 1\times 1\right)+\left(1\times 1\right)-\left(1\times 1\right)$

$=2m$

The displacement covered by the body is $2m$.