Question

The velocity-time graph of a body moving in a straight line as shown. The displacement of the body in 10 s is

Answer 1

$V=\frac{ds}{dt}$
$\text{Displacement}=\int dt=\int Vdt=\text{Area}$
So,
$\text{Displacement}=\text{Area}AOC\text{+ Area}CED+\text{Area}EGFH$
$=\frac{1}{2}\times 6\times 4-\frac{1}{2}\times 2\times 3+2\times 2$
$=12-3+4=13m$