Question

The velocity-time graph of a car is as shown in the figure above.
Find the acceleration and deceleration of the car if its total displacement is $90m$.

Answer 1

$\frac{1}{2}\times v_0\times (6-1)=90$

$\frac{1}{2}\times v_0\times 5=90$

$v_0=36m/s$

Acceleration $=\frac{v_0}{4-1}=\frac{36}{3}=12m/s^2$

Deceleration $=\frac{v_0}{6-4}=\frac{36}{2}=18m/s^2$