The velocity-time graph of a moving body is given below:

Find:

(i) the acceleration in parts AB, BC and CD.

(ii) displacement in each part AB,BC,CD,and

(iii) total displacement.

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Solution

(i) Acceleration in the part AB = Slope of AB
= tan (∠BAD)
= (30/4) ms^-2
= 7.5 ms^-2

Acceleration in the part BC = 0 ms^-2

Acceleration in the part CD = slope of CD = -tan (∠CDA)
= -(30/2) ms^-2
= -15 ms^-2

(ii) Displacement during AB = Area of ΔABE = $\frac{1}{2} \times 4 \times 30$
= 60 m
Displacement during BC = Area of rectangle EBCF
= (30) × (4) = 120 m
Displacement during CD = Area of ΔCFD = $\frac{1}{2} \times 2 \times 30$
= 30 m

(iii) Total displacement = Displacement during AB + Displacement during BC + Displacement during CD
= 60 + 120 + 30 = 210 m

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The velocity-time graph of a moving body is given below: Find: (i) the acceleration in parts AB, BC and CD. (ii) displacement in each part AB,BC,CD,and (iii) total displacement.

The velocity-time graph of a moving body is given below:

Find:

(i) the acceleration in parts AB, BC and CD.

(ii) displacement in each part AB,BC,CD,and

(iii) total displacement.