Question

The velocity-time graph of a moving train is depicted as shown in figure. The average velocity in time interval $OD$ is

• A. $30m/s$
• B. $60m/s$
• C. $45m/s$
• D. $23m/s$

Answer 1

The correct option is A $30m/s$

Area under the $v-t$ graph gives displacement.
$\text{Average velocity}=\frac{\text{Total displacement}}{\text{Total time}}$
Displacement in time $OD=\text{Area of the graph from}t=0\text{to}t=10s=\frac{1}{2}\times 60\times 10$
Average velocity in time interval $OD$ $=\frac{\frac{1}{2}\times 60\times 10}{10}m{s}^{-1}=30m{s}^{-1}$